서울에 위치한 식당 목록 출력하기 mysql

https://school.programmers.co.kr/learn/courses/30/lessons/131118

SELECT A.REST_ID, A.REST_NAME, A.FOOD_TYPE, A.FAVORITES, A.ADDRESS, ROUND(AVG(B.REVIEW_SCORE),2) AS SCORE
FROM REST_INFO AS A
JOIN REST_REVIEW AS B ON A.REST_ID = B.REST_ID
WHERE A.ADDRESS like '서울%'
GROUP BY A.REST_ID
ORDER BY SCORE DESC, A.FAVORITES DESC

1. JOIN
2. WHERE like
3. GROUP BY, 그룹 당 평균 점수 구하기 위해
4. ORDER BY
5. ROUND( 값, 반올림 할 자릿수) 자리수 + 1에서 반올림
6.  AVG